a64l (3) manual page

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a64l, l64a - convert between long and base-64


#include <stdlib.h>

long a64l(char *str64);

char *l64a(long value);


These functions provide a conversion between 32-bit long integers and little-endian base-64 ASCII strings (of length zero to six). If the string used as argument for a64l() has length greater than six, only the first six bytes are used. If longs have more than 32 bits, then l64a() uses only the low order 32 bits of value, and a64l() signextends its 32-bit result.

The 64 digits in the base 64 system are: ‘.’ represents a 0
‘/’ represents a 1
0-9 represent 2-11
A-Z represent 12-37
a-z represent 38-63
So 123 = 59*64^0 + 1*64^1 = “v/".


The value returned by a64l() may be a pointer to a static buffer, possibly overwritten by later calls.

The behaviour of l64a() is undefined when value is negative. If value is zero, it returns an empty string.

These functions are broken in glibc before 2.2.5 (puts most significant digit first).

This is not the encoding used by uuencode(1) .

Conforming to


See Also

uuencode(1) , itoa(3) , strtoul(3)

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